# 2.27   If the solubility product of $\inline CuS$ is $6\times10^{-16}$, calculate the maximum molarity of $\inline CuS$ in aqueous solution.

We are given,    $K_{sp} = 6\times10^{-16}$

The dissociation equation of CuS is given by :-

So, the equation becomes :-   $K_{sp} = Cu^{2+}\times {S^{2-}}$

or                                            $K_{sp} = s\times s = s^2$

or                                                     $s = 2.45\times 10^{-8}\ M$

Thus maximum molarity of solution is   $2.45\times 10^{-8}\ M$.

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