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2.27   If the solubility product of CuS is 6\times10^{-16}, calculate the maximum molarity of CuS in aqueous solution.

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We are given,    K_{sp} = 6\times10^{-16}

  The dissociation equation of CuS is given by :- 

                                      

So, the equation becomes :-   K_{sp} = Cu^{2+}\times {S^{2-}}

or                                            K_{sp} = s\times s = s^2

or                                                     s = 2.45\times 10^{-8}\ M

Thus maximum molarity of solution is   2.45\times 10^{-8}\ M.

Posted by

Devendra Khairwa

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