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(ii) Starting from (– 6) × 3, find (– 6) × (–7)

(ii) Starting from (– 6) × 3, find (– 6) × (–7)

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Given,

(- 6) \times 3 = -18

\\ (-6) \times 2 = -12 = -18 +6 \\ (-6) \times 1 = -6 = -18+12 \\ (-6) \times 0 = 0 = -18 + 18 \\ (-6) \times (-1) = 6 = -18+24 \\ (-6) \times (-2) = 12 = -18+30 \\ \\ (-6) \times (-3) = 18 = -18+36

Therefore,

\\ (-6) \times (-7) = -18+60=42

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