# Q (5) In a circle of diameter 40 cm, the length of a chord is 20 cm. Find the length of minor arc of the chord.

Solution

Given :- radius (r)of circle =

length of chord = 20 cm

We know that
(r = 20cm , l = ? ,  = ?)

Now,

AB is the chord of length 20cm and OA and OB are radii of circle 20 cm each
The angle subtended by OA and OB at centre =
OA = OB = AB
OAB is equilateral triangle
So, each angle equilateral is

Now, we have  and r
So,

the length of the minor arc of the chord (l) =   cm

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