21.(iii) In a class of students, opted for NCC, opted for NSS and opted for both NCC and NSS. If one of these students is selected at random, find the probability that
(iii) The student has opted NSS but not NCC.
Let A be the event that student opted for NCC and B be the event that the student opted for NSS.
n(S) = 60, n(A) = 30, n(B) =32, n(A B) = 24
Therefore, P(A) =
P(A B) =
Probability that the student has opted NSS but not NCC = P(B A' ) = P(B-A)
P(B-A) = P(B) - P(A B)
Hence,the probability that the student has opted NSS but not NCC is
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