# 6.7  In a process, 701 J of heat is absorbed by a system and 394 J of work is done by the system. What is the change in internal energy for the process?

The first law of Thermodynamics state that,
$\Delta U = q+W$

where, $\Delta U$ = change in internal energy for the process
q = heat and W = work

Given that,
q = +701 J (heat is absorbed)
W = - 394 (work is done by the system)

Substituting the value in equation of first law we get,

$\Delta U = 701+(-394) =307J$

So, the change in internal energy for the process is 307 J

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