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12. In Fig, OACB is a quadrant of a circle with centre O and radius 3.5 cm. If OD = 2 cm, find the area of the

       (i) quadrant OACB

                    

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The quadrant OACB is a sector with angle 90o and radius 3.5 cm.

Thus the area of the quadrant is:- 

                                                 =\ \frac{90^{\circ}}{360^{\circ}}\times \pi \times 3.5^2

                                                =\ \frac{77}{8}\ cm^2

Hence the area of the quadrant is    \frac{77}{8}\ cm^2   .

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Devendra Khairwa

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