Q

# In Fig. 6.38, altitudes AD and CE of triangle ABC intersect each other at the point P. Show that: triangle AEP is similar to triangle CDP

Q7 (1)   In Fig. 6.38, altitudes AD and CE of $\Delta ABC$ intersect each other at the point P. Show that:

$\Delta AEP \sim \Delta CDP$

Views

To prove : $\Delta AEP \sim \Delta CDP$

In $\Delta AEP \, \, and\, \, \Delta CDP$,

$\angle AEP=\angle CDP$     ( Both angles are right angle)

$\angle APE=\angle CPD$        (Vertically opposite angles )

$\Delta AEP \sim \Delta CDP$    ( By AA criterion)

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