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Q7  In Fig. 6.38, altitudes AD and CE of \Delta ABC intersect each other at the point P. Show that: \Delta PDC \sim \Delta BEC    

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To prove : \Delta PDC \sim \Delta BEC

In \Delta PDC \, \, and\, \, \, \Delta BEC,

 \angle CDP=\angle CEB     ( Both angles are right angle)

  \angle C=\angle C            (Common )

\Delta PDC \sim \Delta BEC    ( By AA criterion)

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seema garhwal

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