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  • In Fig. 6.38, altitudes AD and CE of triangle ABC intersect each other at the point P. Show that: triangle PDC similar to triangle BEC

Q7 (4)   In Fig. 6.38, altitudes AD and CE of \Delta ABC intersect each other at the point P. Show that:

           \Delta PDC \sim \Delta BEC

           

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To prove : \Delta PDC \sim \Delta BEC

In \Delta PDC \, \, and\, \, \, \Delta BEC,

        \angle CDP=\angle CEB     ( Both angles are right angle)

     \angle C=\angle C        (Common )

\Delta PDC \sim \Delta BEC    ( By AA criterion)

Posted by

seema garhwal

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