Q

# In Fig. 6.40, E is a point on side CB produced of an isosceles triangle ABC with AB = AC. If AD perpendicular BC and EF perpendicular AC, prove that triangle ABD similar triangle ECF.

Q11  In Fig. 6.40, E is a point on side CB produced of an isosceles triangle ABC
with AB = AC. If $AD \perp BC$ and $EF \perp AC$, prove that $\Delta ABD \sim \Delta ECF$

Views

To prove : $\Delta ABD \sim \Delta ECF$

Given: ABC is an isosceles triangle.

$AB=AC \, \, and\, \, \angle B=\angle C$

In $\Delta ABD \, \, and\, \, \Delta ECF$,

$\angle ABD=\angle ECF$         ($\angle ABD=\angle B=\angle C=\angle ECF$)

$\angle ADB=\angle EFC$        ( Each $90 \degree$)

$\Delta ABD \sim \Delta ECF$          ( By AA criterion)

Exams
Articles
Questions