Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • NCERT
  • In Fig. 6.59, ABC is a triangle in which angle ABC < 90° and AD perpendicular BC. Prove that AC square equals AB square plus BC square minus 2 BC . BD.

Q4   In Fig. 6.59, ABC is a triangle in which \angle ABC < 90° and AD \perp BC. Prove that AC^2 = AB^2 + BC^2 - 2 BC . BD.

  

Answers (1)

best_answer

In \triangleADB, by Pythagoras theorem

AB^2=AD^2+DB^2

AD^2=AB^2-DB^2...........................1

In \triangleACD, by Pythagoras theorem

AC^2=AD^2+DC^2

AC^2=AB^2-BD^2+DC^2         (From 1)

\Rightarrow AC^2=AB^2-BD^2+(BC-BD)^2

\Rightarrow AC^2=AB^2-BD^2+(BC)^2+(BD)^2-2.BD.BC

AC^2 = AB^2 + BC^2 - 2 BC . BD.         

 

Posted by

seema garhwal

View full answer

Similar Questions

Trending Articles/News

anam-khan

When will CBSE Class 10 results 2025 be declared? Overall exam paper analysis
anam-khan

CBSE will rope in external agency for skill, vocational subject exams
anam-khan

CBSE adopts new re-evaluation process, split Class 10 science question papers; will test on-screen marking

Latest Question