12.35.    In the estimation of sulphur by Carius method, 0.468 g of an organic sulphur compound afforded 0.668 g of barium sulphate. Find out the percentage of sulphur in the given compound.

Answers (1)
M manish

Given data,

Total mass of the OC = 0.468 g
Mass of barium sulphate formed = 0.668 g 

We know that,

1 mol of BaSO4 = 233 g of BaSO_{4} = 32 g of sulphur
Thus, 0.668 g of BaSO_{4} contains = \frac{32\times 0.668}{233} g of sulphur = 0.0917 g of sulphur

Therefore, the percentage(%) of sulphur 
                                                           = \frac{0.0197}{0.468}\times 100
                                                            = 19.59 %

Hence, the percentage of sulphur in the given compound is 19.59 %.

Preparation Products

Knockout NEET May 2021

An exhaustive E-learning program for the complete preparation of NEET..

₹ 22999/- ₹ 14999/-
Buy Now
Knockout BITSAT 2020

It is an exhaustive preparation module made exclusively for cracking BITSAT..

₹ 4999/- ₹ 1999/-
Buy Now
Knockout NEET May 2022

An exhaustive E-learning program for the complete preparation of NEET..

₹ 34999/- ₹ 24999/-
Buy Now
Knockout JEE Main April 2021

An exhaustive E-learning program for the complete preparation of JEE Main..

₹ 22999/- ₹ 14999/-
Buy Now
Knockout JEE Main April 2022

An exhaustive E-learning program for the complete preparation of JEE Main..

₹ 34999/- ₹ 24999/-
Buy Now
Exams
Articles
Questions