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Q : 3      In the following APs, find the missing terms in the boxes :

             (v)    \small \fbox { },\: 38,\; \fbox { },\: \fbox { },\: \fbox { },\; -22

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Given AP series is
\small \fbox { },\: 38,\; \fbox { },\: \fbox { },\: \fbox { },\; -22
Here, a_2 = 38 , n = 6 \ and \ a_6 = -22
Now,
a_2=a_1+d
a_1=a =38-d \ \ \ \ \ \ \ \ \ -(i)
Now, we know that
a_n = a+(n-1)d
\Rightarrow a_6 =38-d+(6-1)d \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ (using \ (i))
\Rightarrow -22-38-=-d+5d
\Rightarrow d = -\frac{60}{4} = - 15
Now,
a_2= a_1+d
a_1 = 38-(-15) = 38+15 = 53
And 
a_3=a_2+d
a_3=38-15 = 23
And 
a_4 = a_3+d
a_4 = 23-15 = 8
And 
a_5 = a_4 + d
a_5 =8-15 = -7
Therefore, missing terms are   53,23,8,-7 
AP series is 53,38,23,8,-7,-22

Posted by

Gautam harsolia

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