# Q 10.10 In the previous problem, if 15.0 cm of water and spirit each are further poured into the respective arms of the tube, what is the difference in the levels of mercury in the two arms? (Specific gravity of mercury = 13.6)

$\\(\rho _{w}-\rho _{s})gh=\rho _{Hg}gh_{Hg}\\ \left ( 1-\frac{\rho _{s}}{\rho _{w}} \right )h=\frac{\rho _{Hg}}{\rho _{w}}h_{Hg}\\ (1-0.8)\times 15=13.68h_{Hg}\\ h_{Hg}=\frac{0.2\times 15}{13.6}\\ h_{Hg}=0.22cm$