Q : 1     In which of the following situations, does the list of numbers involved make an arithmetic progression, and why?             (iv) The amount of money in the account every year, when  $\small Rs\hspace{1mm}10000$  is deposited at  compound interest at  $\small 8\hspace{1mm}\%$  per annum.

Answers (1)

Amount in the beginning = Rs. 10000

Interest at the end of 1st year at rate of $\small 8\hspace{1mm}\%$
is $\small 8\hspace{1mm}\%$ of 10000 = $\frac{8\times 10000}{100}= 800$

Therefore, amount at the end of 1st year will be

= 10000 + 800

= 10800

Now,

Interest at the end of 2nd year at rate of $\small 8\hspace{1mm}\%$
is  $\small 8\hspace{1mm}\%$ of 10800 =$\frac{8\times 10800}{100}= 864$

Therefore,, amount at the end of 2ndyear

= 10800 + 864 = 11664

Since, each subsequent term is not obtained by adding a unique number to the previous term; hence, it is not an AP

Exams
Articles
Questions