Q : 1     In which of the following situations, does the list of numbers involved make an arithmetic progression, and why?

             (iv) The amount of money in the account every year, when  \small Rs\hspace{1mm}10000  is deposited at  compound interest at  \small 8\hspace{1mm}\%  per annum.

Answers (1)

Amount in the beginning = Rs. 10000

Interest at the end of 1st year at rate of \small 8\hspace{1mm}\%
is \small 8\hspace{1mm}\% of 10000 = \frac{8\times 10000}{100}= 800

Therefore, amount at the end of 1st year will be

= 10000 + 800

= 10800

Now,

Interest at the end of 2nd year at rate of \small 8\hspace{1mm}\%
is  \small 8\hspace{1mm}\% of 10800 =\frac{8\times 10800}{100}= 864

Therefore,, amount at the end of 2ndyear

= 10800 + 864 = 11664

Since, each subsequent term is not obtained by adding a unique number to the previous term; hence, it is not an AP

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