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Q1: In which of the following situations, does the list of numbers involved make an arithmetic progression, and why?

(iii) The cost of digging a well after every metre of digging, when it costs  \small Rs\hspace{1mm}150  for the first metre and rises by  \small Rs\hspace{1mm}50  for each subsequent metre.

Answers (1)

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It is given that the cost of digging a 1st metre = Rs 150
and rises by  \small Rs\hspace{1mm}50  for each subsequent metre
Therefore,

cost of digging the first 2 metres = cost of digging the first metre + cost of digging additional metre

cost of digging the first 2 metres = 150 + 50

                                                   =  Rs 200

Similarly,
The cost of digging the first 3 metres = cost of digging the first 2 metres + the cost of digging an additional metre

Cost of digging the first 3 metres = 200 + 50

                                                  =  Rs 250

We can clearly see that 150, 200, 250,... is in AP with each subsequent term is obtained by adding a fixed number (50) to the previous term.

Therefore, it is an AP with first term (a) = 150 and common difference (d) = 50

Posted by

Gautam harsolia

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