8.15  Justify giving reactions that among halogens, fluorine is the best oxidant and among hydrohalic compounds, hydroiodic acid is the best reductant.

Answers (1)

Answer-

part(i)

Fluorine can oxidize other halogen ions. On the other hand Br_{2},I_{2},Cl_{2}  cannot oxidize 2F^{-} \rightarrow F_{2}

F_{2}+2I^{-}\rightarrow 2F^{-}+I_{2} \\F_{2}+2Br^{-}\rightarrow 2F^{-}+Br_{2} \\F_{2}+2Cl^{-}\rightarrow 2F^{-}+Cl_{2}  

And hence we say that fluorine is the better oxidant among halogen.

part(ii)

HI &HBr are able to reduce H_{2}SO_{4}\rightarrow SO_{2} but HCl,HF are unable to reduce sulphuric acid.

So here we can say that HI &HBr are better reductant than HCl,HF.

Again I^{-} can only able to reduce Cu^{2+}\rightarrow Cu^{+} but Br^{-} cannot.

4I^{-}+2Cu^{2+}\rightarrow Cu_{2}I_{2}+I_{2}

Hence among hydrohalic compound hydroiodic acid is the best reductant.

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