8.3 Justify that the following reactions are redox reaction

(c) 4BCl_{3}_{(g)}+3LiAlH_{4}_{(s)}\rightarrow 2B_{2}H_{6}_{(g)}+3LiCl_{(s)}+3AlCl_{3}_{(s)}

Answers (1)

Solution-

Let us write the O.N of each element

4\overset{+3\:\:-1}{BCl_{3}}\:\:+\:3\overset{+1\:\:+3\:\:-1}{LiAlH_{4}}\:\rightarrow\:2\overset{-3\:\:+1}{B_{2}H_{6}}\:\:+\:\:3\overset{+1\:-1}{LiCl}\:\:+\:3\overset{+3\:-1}{AlCl_{3}}

Here, the O.N of Fe decreases from +3 in BCl3  to 3 in B2H6. And, the O.N of H increases from –1 in LiAlH_{4} to +1 in B_{2}H_{6} . Hence it is a redox reaction.

 

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