Q

Justify that the following reactions are redox reactions 4BCl3(g) + 3LiAlH4(s) → 2B2H6(g) + 3LiCl(s) + 3 AlCl3(s)

8.3 Justify that the following reactions are redox reaction

(c) $4BCl_{3}_{(g)}+3LiAlH_{4}_{(s)}\rightarrow 2B_{2}H_{6}_{(g)}+3LiCl_{(s)}+3AlCl_{3}_{(s)}$

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Solution-

Let us write the O.N of each element

$4\overset{+3\:\:-1}{BCl_{3}}\:\:+\:3\overset{+1\:\:+3\:\:-1}{LiAlH_{4}}\:\rightarrow\:2\overset{-3\:\:+1}{B_{2}H_{6}}\:\:+\:\:3\overset{+1\:-1}{LiCl}\:\:+\:3\overset{+3\:-1}{AlCl_{3}}$

Here, the O.N of Fe decreases from +3 in BCl3  to 3 in B2H6. And, the O.N of H increases from –1 in $LiAlH_{4}$ to +1 in $B_{2}H_{6}$ . Hence it is a redox reaction.

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