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Q.8    LetA and B be independent events with P(A)=0.3 and P(B)=0.4  Find

             (ii)  P(A\cup B)

Answers (1)


P(A)=0.3  and P(B)=0.4

Given :  A and B be independent events

So, we have 

                       P(A\cap B)=P(A).P(B)

                        P(A\cap B)=0.3\times 0.4=0.12

   We have,    P(A\cup B)=P(A)+P(B)-P(A\cap B)

                    P(A\cup B)=0.3+0.4-0.12=0.58


Posted by

seema garhwal

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