# Q5  S and T are points on sides PR and QR of $\Delta$  PQR such that $\angle$ P = $\angle$ RTS. Show that          $\Delta$ RPQ ~ $\Delta$ RTS.

S seema garhwal

Given : $\angle$ P = $\angle$ RTS

To prove :          $\Delta$ RPQ ~ $\Delta$ RTS.

In  $\Delta$ RPQ  and  $\Delta$ RTS,

$\angle$ P = $\angle$ RTS    (Given )

$\angle$ R = $\angle$ R         (common)

$\Delta$ RPQ ~ $\Delta$ RTS.  ( By AA)

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