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  • (b) Shows that the projection angle theta_0 for a projectile launched from the origin is given by

Q. 4.32 (b) Shows that the projection angle \theta _{0} for a projectile launched from the origin is given by

 \theta _{0}=tan^{-1}\left [ \frac{4h_{m}}{R} \right ]

where the symbols have their usual meaning.

Answers (1)

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(b)     The maximum height is given by   : 

                                                                     h\ =\ \frac{u^2 \sin^2 \Theta }{2g}

And,     the horizontal range is given by  :

                                                                     R\ =\ \frac{u^2 \sin 2\Theta }{g}

Dividing both, we get : 

                                                                    \frac{h}{R}\ =\ \frac{\tan \Theta }{4}

Hence                                                          \Theta \ =\ \tan^{-1} \left ( \frac{4h }{R} \right ) 

Posted by

Devendra Khairwa

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