# Solve each of the following equations: Q : 7        $\sqrt{2}x^2+x+\sqrt{2}=0$

$\sqrt{2}x^2+x+\sqrt{2}=0$
$\frac{-b\pm \sqrt{b^2-4ac}}{2a}$
In this case the value of $a = \sqrt 2 , b =1 \ and \ c = \sqrt2$
$\frac{-1\pm \sqrt{1^2-4.\sqrt2.\sqrt2}}{2.\sqrt2}= \frac{-1\pm\sqrt{1-8}}{2\sqrt2} = \frac{-1\pm\sqrt{-7}}{2\sqrt2}=\frac{-1\pm\sqrt{7}i}{2\sqrt2}$
Therefore, the solutions of the equation are   $\frac{-1\pm\sqrt{7}i}{2\sqrt2}$