Solve each of the following question using appropriate Euclid’s axiom: In the Fig. 5.10, we have AC = DC, CB = CE. Show that AB = DE.
Given:
AC = DC, CB = CE
To prove: AB = DE
Euclid axiom says that if equals added to equals, then wholes are also equal. Now, as
AC = DC, CB = CE
We can write:
AC + CB = DC + CE
{ AB= AC + CB; DE = DC + CE}
AB = DE
Hence proved.