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Solve each of the following questions using appropriate Euclid’s axiom: In Fig. 5.10, we have AC = DC, CB = CE. Show that AB = DE.

Answers (1)

Given:

AC = DC, CB = CE

To prove: AB = DE

Euclid's axiom says that if equals are added to equals, then wholes are also equal. Now, as

AC = DC, CB = CE

We can write:

AC + CB = DC + CE

{\because AB= AC + CB; DE = DC + CE}

 AB = DE

Hence proved.

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