Go To Your Study Dashboard

Get Answers to all your Questions

header-bg

Q1. Solve the following pair of linear equations by the substitution method.

(vi) $\\\frac{3x}{2} - \frac{5y}{3}= - 2\\ \frac{x}{3} + \frac{y}{2} = \frac{13}{6}$

Answers (1)

best_answer

Given,

$\\\frac{3x}{2} - \frac{5y}{3}= - 2.........(1)\\ \frac{x}{3} + \frac{y}{2} = \frac{13}{6}.............(2)$

From (1) we have,

$x=\frac{2}{3}\left ( \frac{5y}{3}-2 \right )........(3)$

Putting this in (2) we get,

$\frac{1}{3}\times\frac{2}{3}\left ( \frac{5y}{3}-2 \right )+\frac{y}{2}=\frac{13}{6}$

$\frac{10y}{27}-\frac{4}{9}+\frac{y}{2}=\frac{13}{6}$

$\frac{20y}{54}-\frac{4}{9}+\frac{27y}{54}=\frac{13}{6}$

$\frac{47y}{54}=\frac{13}{6}+\frac{4}{9}$

$\frac{47y}{54}=\frac{117}{54}+\frac{24}{54}$

$47y=117+24$

$47y=141$

$y=\frac{141}{47}$

$y=3$

putting this value in (3) we get,

$x=\frac{2}{3}\left ( \frac{5y}{3}-2 \right )$

$x=\frac{2}{3}\left ( \frac{5\times3}{3}-2 \right )$

$x=\frac{2}{3}\left (5-2 \right )$

$x=\frac{2}{3}\times 3$

$x=2$

Hence $x=2\:\:and\:\:y=3.$

Posted by

Pankaj Sanodiya

View full answer

Similar Questions

Trending Articles/News

anam-khan

CBSE 2026 10th Exam May 15 LIVE: Session 2 maths 'easier'; question paper with answer key, analysis

anam-khan

CBSE 10th Admit Card 2026 (OUT) LIVE: Phase 2 hall ticket issued at cbse.gov.in; datesheet, paper timings

anam-khan

CBSE 2nd Board exam 2026 class 10 admit card out at cbse.gov.in; steps to download

Latest Question