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The 17th term of an AP exceeds its 10th term by 7. Find the common difference.

Q : 10      The \small 17th term of an AP exceeds its \small 10th term by \small 7. Find the common difference.
 

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It is given that
\small 17th term of an AP exceeds its \small 10th term by \small 7
i.e.
a_{17}= a_{10}+7
\Rightarrow a+16d = a+9d+7
\Rightarrow a+16d - a-9d=7
\Rightarrow 7d=7
\Rightarrow d = 1
Therefore, the common difference of AP is 1

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