Q : 10      The \small 17th term of an AP exceeds its \small 10th term by \small 7. Find the common difference.
 

Answers (1)

It is given that
\small 17th term of an AP exceeds its \small 10th term by \small 7
i.e.
a_{17}= a_{10}+7
\Rightarrow a+16d = a+9d+7
\Rightarrow a+16d - a-9d=7
\Rightarrow 7d=7
\Rightarrow d = 1
Therefore, the common difference of AP is 1

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