# The circuit in Figure shows two cells connected in opposition to each other. Cell $E_{1}$ is of emf 6V and internal resistance 2$\Omega$; the cell $E_{2}$ is of emf 4V and internal resistance 8$\Omega$. Find the potential difference between the points A and B.

Equivalent EMF of the Cells $=6V-4V=2V$

$R_{eq}=2\Omega +8\Omega=10\Omega$

$I=\frac{2V}{10 \Omega}=0.2A$

$V_B-V_A=4+8\times 0.2=5.6V$

## Similar Questions

### Preparation Products

##### Knockout NEET May 2021 (One Month)

An exhaustive E-learning program for the complete preparation of NEET..

₹ 14000/- ₹ 6999/-
##### Foundation 2021 Class 10th Maths

Master Maths with "Foundation course for class 10th" -AI Enabled Personalized Coaching -200+ Video lectures -Chapter-wise tests.

₹ 350/- ₹ 112/-
##### Knockout JEE Main April 2021 (One Month)

An exhaustive E-learning program for the complete preparation of JEE Main..

₹ 14000/- ₹ 6999/-
##### Knockout NEET May 2021

An exhaustive E-learning program for the complete preparation of NEET..

₹ 22999/- ₹ 14999/-