3.8 The conductivity of 0.20 M solution of KCl at 298 K is 0.0248 S cm–1. Calculate its molar conductivity.

Answers (1)

We know that the molar conductivity of a solution is defined as:- 

                                                 \Lambda _M\ = \frac{\kappa }{C}

Putting the value of conductivity and concentration in the above equation:- 

                                                   \Lambda _M\ = \frac{0.0248\times1000 }{0.20} = 124\ Scm^2\ mol^{-1}

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