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The following is the distance-time table of an object in motion: (a)

Q A1.     The following is the distance-time table of an object in motion:                 

        

Time in seconds  Distance in metre
0 0
1 1
2 8
3 27
4 64
5 125
6 216
7 343

 

    (a)     What conclusion can you draw about the acceleration? Is it constant, increasing, decreasing, or zero? 

Answers (1)
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From the table, the relation between time and the distance can be seen.

                                                                       s\ =\ t^3

Thus the velocity of the particle is increasing with time.      

                                                                     v\ =\ \frac{ds}{dt}\ =\ 3t^2

and                                                               a\ =\ \frac{dv}{dt}\ =\ 6t                    

Hence acceleration increases linearly with time.  

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