Q A1.     The following is the distance-time table of an object in motion:                 

        

Time in seconds  Distance in metre
0 0
1 1
2 8
3 27
4 64
5 125
6 216
7 343

 

    (a)     What conclusion can you draw about the acceleration? Is it constant, increasing, decreasing, or zero? 

Answers (1)

From the table, the relation between time and the distance can be seen.

                                                                       s\ =\ t^3

Thus the velocity of the particle is increasing with time.      

                                                                     v\ =\ \frac{ds}{dt}\ =\ 3t^2

and                                                               a\ =\ \frac{dv}{dt}\ =\ 6t                    

Hence acceleration increases linearly with time.  

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