The kinetic energy of an object of mass, m moving with a velocity of 5 \; m\; s ^{-1}  is 25\; J. What will be its kinetic energy when its velocity is doubled?

What will be its kinetic energy when its velocity is increased three times?

Answers (1)

Using the formula for the kinetic energy we have :

                                                          K.E\ =\ \frac{1}{2}mv^2

or                                                           25\ =\ \frac{1}{2}m\times 5^2

or                                                             m\ =\ 2\ Kg

(i) Kinetic energy when velocity is doubled :

                                                        K.E\ =\ \frac{1}{2}mv^2

                                                                    =\ \frac{1}{2}\times2 \times 10^2

                                                                    =\ 100\ J

(ii) Kinetic energy when velocity is tripled :

                                                         K.E\ =\ \frac{1}{2}mv^2

                                                                     =\ \frac{1}{2}\times 2\times 15^2

or                                                                 =\ 225\ J

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