# 2.13    The partial pressure of ethane over a solution containing $\inline 6.56\times 10^{-3}\; g$ of ethane is 1 bar. If the solution contains $\inline 5.00\times 10^{-2}g$ of ethane, then what shall be the partial pressure of the gas?

D Devendra Khairwa

Using Henry's Law we can write,

$m = k.P$

Putting value in this equation, we get :

$6.56\times10^{-3} = k\times 1$

So, the magnitude of k is   $6.56\times10^{-3}$.

Now, we will again use the above equation for  $m = 5.0\times10^{-2}\ g$.

So the required partial pressure is :-

$p = \frac{m}{k} = \frac{5.0\times10^{-2}}{6.56\times10^{-3}}$

or                                                    $p = 7.62\ bar$

Exams
Articles
Questions