# Q 2.9: The photograph of a house occupies an area of 1.75 $cm^2$ on a 35 $mm$ slide. The slide is projected on to a screen, and the area of the house on the screen is 1.55 $m^2$. What is the linear magnification of the projector-screen arrangement.

Given,

Area of the house in the photo = $1.75\ cm^{2}$

Area of the house on the screen = $1.55 m^{2} = 1.55 \times10^{4} cm^2$

$\therefore$ Arial magnification, $m_{a}$ = Area on the screen / area on photo = $\frac{1.55\times 10^{4}}{1.75} = 0.886 \times 10^4$

Linear magnification of the projector- screen arrangement  $m_{l} = \sqrt{m_{a}} = \sqrt{.886 \times 10^{4}}= 94.1$

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