# Q 3.27  The speed-time graph of a particle moving along a fixed direction is shown in Figure. Obtain the distance traversed by the particle between(a) t = 0 s to 10 sWhat is the average speed of the particle over the intervals in (a) and (b)?

The distance traversed by the particle equals the area under the speed time graph

The area under the curve is

$\\A=\frac{1}{2}\times 10\times 12\\ A=60\ m$

The particle has travelled a distance of 60 m from t=0 s to t=10 s.

The average speed over this interval is

$\\v_{avg}=\frac{60}{10}\\ v_{avg}=6\ ms^{-1}$

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