# Q 3.27  The speed-time graph of a particle moving along a fixed direction is shown in Figure. Obtain the distance traversed by the particle between(b) t = 2 s to 6 s. What is the average speed of the particle over the intervals in (a) and (b)?

As the speed is increasing in the time interval t = 0 s to t = 5 s the acceleration is positive and can be given by

Speed at t = 2 s is

Speed at t = 5 s is v1 = 15 m s-1

t= 5 - 2 = 3 s

Distance travelled in interval t = 2 s to t = 5 s is s1

Acceleration is negative after t = 5 s but has the same magnitude

a= -2.4 m s-2

Speed at t =  5 s is u2 = 12 m s-1

t= 6 - 5 = 1 s

Distance travelled in this interval can be calculated as follows

Total distance travelled from t = 2 s to t = 6 s is s = s1 + s2

s=25.2+10.8

s=36 m

The average speed over this interval is

## Related Chapters

### Preparation Products

##### Knockout NEET Sept 2020

An exhaustive E-learning program for the complete preparation of NEET..

₹ 15999/- ₹ 6999/-
##### Rank Booster NEET 2020

This course will help student to be better prepared and study in the right direction for NEET..

₹ 9999/- ₹ 4999/-
##### Knockout JEE Main Sept 2020

An exhaustive E-learning program for the complete preparation of JEE Main..

₹ 12999/- ₹ 6999/-
##### Test Series NEET Sept 2020

Take chapter-wise, subject-wise and Complete syllabus mock tests and get in depth analysis of your test..

₹ 4999/- ₹ 2999/-