# 8.(viii) Three coins are tossed once. Find the probability of getting (viii) no tail

Answers (1)
H Harsh Kankaria

Sample space when three coins are tossed: [Same as a coin tossed thrice!]

S = {HHH, HHT, HTH, HTT, THH, TTH, THT, TTT}

Number of possible outcomes, n(S) = 8                             [Note: 2x2x2 = 8]

Let E be the event of getting no tail = Event of getting only heads = {HHH}

$\therefore$ n(E) = 1

$\therefore$ $\dpi{100} P(E) = \frac{n(E)}{n(S)}$  $= \frac{1}{8}$

The required probability of getting no tail is $\dpi{80} \frac{1}{8}$.

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