# Q17  Tick the correct answer and justify : In $\Delta ABC$  AB = $6 \sqrt 3$  cm, AC = 12 cm and BC = 6 cm. The angle B is : (A) 120°(B) 60°(C) 90°(D) 45°

In $\Delta ABC$  AB = $6 \sqrt 3$  cm, AC = 12 cm and BC = 6 cm.

$AB^2+BC^2=108+36$

$=144$

$=12^2$

$=AC^2$

It satisfies the pythagoras theorem.

Hence, ABC is a right angled triangle and right angled at B.

Option C is correct.

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