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Two cells of the same emf E but internal resistance $r_{1}$ and $r_{2}$ are connected in series to an external resistor R (Figure). What should be the value of R so that the potential difference across the terminals of the first cell becomes zero?

Answers (1)

$EMF_{ef}=E+E=2E$

$R_{ef}=r_1+r_2$

$I=\frac{2E}{R+r_1+r_2}$

As the net potential across the cell is 0,

$E-Ir_1=0$

$E-\frac{2Er_1}{R+r_1+r_2}=0$

The value of R should be, $R=r_1-r_2$

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