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Q.8.    Two children are at opposite ends of an aluminium rod. One strikes the end of the rod with a stone. Find the ratio of times taken by the sound wave in air and in aluminium to reach the second child.

(Given: Speed of sound in air is  346\ m/s; Speed of sound in aluminium is 6240\ m/s )

Answers (1)


Here, let us assume the length of the rod be 'l'.


Time taken by the sound wave in air:

\left ( Given: v_{air} = 346\ m/s \right )

Time = \frac{Distance}{Speed}

t_{air} = \frac{l}{346} seconds

Time taken by the sound wave in Aluminium to reach from one end to the other end,

\left ( Given: v_{aluminium} = 6420\ m/s \right )

t_{aluminium} = \frac{l}{6420} seconds

Therefore, the ratio of the time taken by the sound wave in air and in aluminium will be:

\frac{t_{air}}{t_{aluminium}} = \frac{\frac{l}{346}}{\frac{l}{6420}} = \frac{6420}{346} = \frac{18.55}{1}

Hence, the ratio is 18.55:1.



Posted by

Ritika Kankaria

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