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Using the standard electrode potentials given in Table:3.1

3.17    Using the standard electrode potentials given in Table 3.1, predict if the reaction between the following is feasible:        

    (iii)   Fe^{3+}_{aq}\: and\ Br^{-}_{aq}

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A reaction is feasible only if  E_{cell} ^{\circ}  is positive.

So, anode and cathode reactions will be as follows :- 

                                           (Fe^{+3}\ +\ e^-\ =\ Fe^{+2})\times 2                                E^{\circ}\ = 0.77\ V

                                                              2Br^-\ =\ Br_2\ +\ 2e^-                     E^{\circ}\ = -1.09\ V

and                                  E_{cell} ^{\circ} = 0.77 - 1.09 = -0.32\ V

So this reaction is not feasible.

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