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1.11    What is the concentration of sugar (C12H22O11) in mol L–1 if its 20 g are dissolved in enough water to make a final volume up to 2L?

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The molar mass of sugar  C_{12}H_{22}O_{11} is:

= (12\times12)+ (1\times 22)+(11\times16) = 342g\ mol^{-1}.

The number of moles of sugar in 20g of sugar will be:

= \frac{20}{342} = 0.0585\ mole

and given the volume of the solution after dissolving enough water is 2L.

 Molar\ concentration = \frac{Moles\ of\ solute}{Volume\ of\ solution\ in\ 1L}

= \frac{0.0585mol}{2L} = 0.0293mol\ L^{-1} = 0.0293\ M

Posted by

Divya Prakash Singh

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