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# What would be the SI unit for the quantity pV^2 T^2/n ?

5.20     What would be the $SI$ unit for the quantity $pV^{2}T^{2}/n$ ?

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Given quantity, $pV^{2}T^{2}/n$,

The SI units of each factors are,

For pressure p is $Nm^{-2}$.

For Volume V is $m^3$.

For Temperaute T is$K$.

For number of moles, n is mol.

Therefore we have for the quantity

The SI unit is $=\frac{(Nm^{-2})(m^3)^2)(K)^2}{mol}$

$= Nm^4K^2 mol^{-1}$

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