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5.20: What would be the SI unit for the quantity pV^{2}T^{2}/n?

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Given quantity, pV^{2}T^{2}/n,

The SI units of each factors are,

For pressure, p is Nm^{-2}.

For volume V is m^3.

For temperature T isK.

For number of moles, n is mol.

Therefore, we have a quantity 

The SI unit is =\frac{(Nm^{-2})(m^3)^2)(K)^2}{mol}

= Nm^4K^2 mol^{-1}

Posted by

Divya Prakash Singh

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