8.16   Why does the following reaction occur?

XeO_{6}^{4-}(aq)+2F^{-}(aq)+6H^{+}(aq)\rightarrow XeO_{3}(g)+F_{2}(g)+3H_{2}O(l)

 What conclusion about the compound Na_{4}XeO_{6}   (of whichXeO_{6}^{4-} is a part) can be drawn from the reaction ?

Answers (1)

Answer-

we conclude that the oxidation state of Xenon changes from  +8 to +6

XeO_{6}^{4-} (+8)\rightarrow XeO_{3}(+6)

and oxidation state of F changes from -1 to 0

F^{-}(-1)\rightarrow F_{2}(0)

Na_{4}XeO_{6}  is reduced by accepting an electron.

It is a strong oxidizing agent than F 

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