# Write the additive inverse of each of the following:(i) $\frac{2}{8}$                           (ii)$\frac{-5}{9}$                    (iii) $\frac{-6}{-5}$               (iv) $\frac{2}{-9}$              (v)$\frac{19}{-6}$

(i) The additive inverse of  $\\ \\ \frac{2}{8}$ is $\frac{-2}{8}$  because  $\frac{2}{8}+\frac{-2}{8} = \frac{2-2}{8} = 0$

(ii) The additive inverse of $\frac{-5}{9}$ is $\frac{5}{9}$  because  $\frac{-5}{9}+\frac{5}{9} = \frac{-5+5}{9} = 0$

(iii) The additive inverse of  $\frac{-6}{-5}$  is $\frac{6}{-5}$  because $\frac{-6}{-5}+\frac{6}{-5} = \frac{-6+6}{-5} = 0$

(iv) The additive inverse of $\frac{2}{-9}$ is $\frac{-2}{-9}$  because $\frac{2}{-9}+\frac{-2}{-9} = \frac{2-2}{-9} = 0$

(v) The additive inverse of $\frac{19}{-6}$ is $\frac{-19}{-6}$  because $\frac{19}{-6}+\frac{-19}{-6} = \frac{19-19}{-6} =0$

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