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  • Write the general term in the expansion of (x^2 - yx) ^ 12, x not equal to 0

Write the general term in the expansion of

    Q4.    (x^2 - xy)^{12}, \ x\neq 0

Answers (1)

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As we know that the general  (r+1)^{th} term  T_{r+1} in the binomial expansion of  (a+b)^n  is given by 

T_{r+1}=^nC_ra^{n-r}b^r

So the general term of the expansion of (x^2 - xy)^{12}, is

\\\Rightarrow T_{r+1}\\=^{12}C_r(x^2)^{12-r}(-xy)^r\\=(-1)^r\times^{12}C_rx^{24-2r+r}y^r\\=(-1)^r\times^{12}C_rx^{24-r}y^r.

Posted by

Pankaj Sanodiya

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