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  • the equation of perpendicular bisector of a line segment AB is x-y+5=0 if a=(1,-2) then AB is

the equation of perpendicular bisector of a line segment AB is x-y+5=0 if a=(1,-2) then AB is

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best_answer Perpendicular to AB is x-y+5=0 y=x+5 Standard equation of line is y=m x+c where slope is m so slope of line perpendicular to AB = 1 so slope of AB = -1 equation of line AB is: y=-x+c AB passes through (1,-2) thus, -2=-1+c c = -1 Equation of line AB with slope(-1) : y=-x-1 or x+y+1=0
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Deependra Verma

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