10125 joules of heat energy boils off 4.5 g of water at 100-degree Celsius to steam at 100-degree celsius .find the specific latent heat of steam

Answers (1)

Latent heat of steam (L)  is the heat energy required to convert 1 kg of water at 100°C at 1 atmospheric pressure to steam at 100°C

\begin{aligned} &m L=10125\\ &4.5 \times L=10125\\ &\mathrm{L}=\frac{10125}{45} \times 10=2250 \mathrm{J} / \mathrm{g} \end{aligned}

 

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