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  • 20. A point of application of a force F = 5i - 3j + 2k is moved from r1 = 2i+7j+4k to r2 = -5i+2j+ 3k. The work done will be (a) - 22 units (b) 22 uniG (c) 11 units (d) - 11 unis

20. A point of application of a force F = 5i - 3j + 2k is moved from r1 = 2i+7j+4k to r2 = -5i+2j+ 3k. The work done will be (a) - 22 units (b) 22 uniG (c) 11 units (d) - 11 unis

Answers (2)

Work fone = F.ds=(5i-3j+2k). (r2-r1)

=

(5i-3j+2k). (-7i-5j-1k)=-35+15-2=-22 units

Posted by

Safeer PP

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11 units

 

 

Posted by

MOHANGANESH

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