58 cube minus 24 whole cube minus 34 whole cube in simplest form ?

Answers (1)

Using the formula,(a^3-b^3)=(a-b)(a^2+ab+b^2)
Given question is
58^3-24^3-34^3
=(58-24)(58^2+58*24+24^2)-34^3
=34*[58^2+24(58+24)-34^2]
=34*[(58+34)(58-34)+24*82]
=34*[(58+34)(58-34)+24*82]
=34*[92*24+24*82]
=34*24*174
=17*12*4*(175-1)
=17*12*(700-4)
=17*6*(1400-8)
=102*1400-8*102
=142,800-816
=141,984

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