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(a) 1·0 g of a non-electrolyte solute dissolved in 50 g of benzene lowered the freezing point of benzene by 0·40 K. The freezing point depression constant of benzene is 5.12\: K\: kg\: mol^{-1} . Find the molar mass of the solute.

(b) What is the significance of Henry’s law constant, K_H ?

(c) What leads to anoxia ?

 

 

 

 
 
 
 
 

Answers (1)

(a)Mass of non - electrolyte solute = 1 g  (W_2)

Mass of benzene = 50 g  (W_1)

\Delta T_f=0.40K

Molar mass of solute = ?  (M_2)

\begin{aligned} &\Delta T_{f}=\frac{K_{f} \times W_{2} \times 1000}{M_{2} \times W_{1}}\\ &M_{2}=\frac{ K_{f} \times W_{2} \times 1000}{\Delta T_{f} \times W_{1}}\\ &=\frac{5.12 \times 1 \times 1000}{0.40 \times 50}\\ &=256 \mathrm{g} / \mathrm{mol} \end{aligned}

(b) Significance of Henry's constant. It increases with increase in temperature and more is the value of  K_H, less is the solubility. So it tells about the solubility of gases in liquids depending on temperature.

(c) People living at high altitudes suffer from anoxia as they have low concentration of oxygen in their blood since pressure of air is less which makes them work. 

Posted by

Sumit Saini

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