A 4% solution (w/w) of sucrose (M = 342 g mol-1) in water has freezing point of 271.15K. Calculate the freezing point of 5% glucose (M = 180 g mol^{-1}) in water.

(Given: Frezzing point of water = 273.15K)

 

 

 

 
 
 
 
 

Answers (1)
S Sumit

\Delta T_{f}= K_{f}\times m

            = 16.41 \times \frac{5}{180}\times \frac{1000}{45}=4.8K

\Delta T_{f}= T^{\circ}_{f}- T_{f}

4.8=273.15-T_{f}

T_{f}-268.35K

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