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  • A 5 cm tall object is placed at a distance of 30 cm from a convex mirror of focal length 15 cm. Find the position, size and nature of the image formed.       <div sty

A 5 cm tall object is placed at a distance of 30 cm from a convex mirror of focal length 15 cm. Find the position, size and nature of the image formed.

 

 

 

 
 
 
 
 

Answers (2)

Convex Mirror

\\u = - 30 cm \\ f = +15 cm \\ h = 5cm

From Mirror Formula

        \frac{1}{f} = \frac{1}{u} + \frac{1}{v}

\Rightarrow \frac{1}{15} = \frac{-1}{30} + \frac{1}{v}

\Rightarrow v = +10 cm

    \frac{h_2}{h_1} = \frac{-v}{u}

    h_2 = \frac{-(+10)}{(-30)} \times (+5)

    h_2 = \frac{5}{3}

    h_2 =+1.66 cm

Nature: Virtual and erect.

Posted by

Sumit Saini

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Given, convex mirror (diverging mirror)

u = -30 cm 

h = +5 cm 

f = +15 cm 

By mirror formula

1/f = 1/v + 1/u

1/15 = 1/v + 1/-30

1/v = 3/30

v= +10 cm 

= h'/h  = -v/u 

h'/5 = -10/-30

h' = 5/3

h'= +1.66 cm 

Nature = virtual and errect

 

 

 

 

 

 

 

 

 

 

 

 

 

Posted by

Aditya Mudgal

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