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A 6 cm tall object is placed perpendicular to the principal axis of a concave mirror of focal length 30 cm. The distance of the object from the mirror is 45 cm. Use mirror formula to determine the position, nature and size of the image formed. Also draw labelled ray diagram to show the image formation in this case. 

 

 

 

 
 
 
 
 

Answers (2)

best_answer

h = 6cm

f = -30cm

u = -45

\frac{1}{f}=\frac{1}{v}+\frac{1}{u}

\frac{1}{v}=\frac{1}{f}-\frac{1}{u}

\frac{1}{v}=\frac{1}{(-30)}-\frac{1}{(-45)}

\frac{1}{v}=-\frac{1}{90}

v = -90cm from the pole of the mirror

Size of the image

m = \frac{-v}{u}=-\frac{90}{45}

m = -2

ux\Rightarrow m = \frac{h'}{h}\Rightarrow h' = -2\times 6 = -12 cm

 

Posted by

Sumit Saini

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Kalesh

Posted by

Kalesh

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